4x^2+6x-1800=0

Solution for 4x^2+6x-1800=0 equation:

4x^2+6x-1800=0

a = 4; b = 6; c = -1800;
Δ = b2-4ac
Δ = 62-4·4·(-1800)
Δ = 28836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28836}=\sqrt{324*89}=\sqrt{324}*\sqrt{89}=18\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18\sqrt{89}}{2*4}=\frac{-6-18\sqrt{89}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18\sqrt{89}}{2*4}=\frac{-6+18\sqrt{89}}{8}
$